📈write the slope intercept form of the equation for the line.Y=2x1Y=1
2X 3Y 9 In Slope Intercept Form. (a) parallel to the given line, and (b) perpendicular to it. Y = mx + c m is the gradient c is the intercept which is the point at x = 0 where the line cuts the y axis.
📈write the slope intercept form of the equation for the line.Y=2x1Y=1
Select two x x values, and plug them into the equation to find the corresponding y y values. 2x +3y = 9 3y = −2x + 9 y = − 2 3 x +9 so the slope or gradient. Subtract from both sides of the equation. In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3 Subtract from both sides of the equation. Divide each term in by and. M = 2 3 m = 2 3 A straight line graph is of the form: The slope is further given by the. Rearrange the equation by subtracting what is to the.
Divide each term in by and. The slope is further given by the. (a) parallel to the given line, and (b) perpendicular to it. So we get our equation into this form: Subtract from both sides of the equation. In slope intercept form 3y = 2x + 9 y = ( 2x + 9)/3 y = 2/3 x + 3 They've given me a reference line, namely, 2x − 3y = 9; Subtract from both sides of the equation. (0,3) ( 0, 3) any line can be graphed using two points. Y = 2 3x− 3. M = 2 3 m = 2 3
